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SarthiQ

Interview Preparation Guide

Meta
Questions & Answers

A comprehensive, expert-curated list of real interview questions to help you prepare effectively and land your dream job.

Document Details

Topic / Subject
Meta
Content Length
41 Curated Q&A
Generated On
October 4, 2026
Provided By
SarthiQ.com
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Meta Interview Questions

Practice with real Meta interview questions

01
A Software Engineer was asked
SarthiQ Meta
Medium
Asked in 2025
Q. Demonstrate how to reverse a string in Java without using built-in methods.
Ans. To reverse a string in Java without using built-in methods like StringBuilder.reverse(), you can use a character array. Here's how:
java
public class StringReversal {
    public static String reverseString(String input) {
        if (input == null || input.isEmpty()) {
            return input;
        }

        char[] characters = input.toCharArray();
        int left = 0;
        int right = characters.length - 1;

        while (left < right) {
            char temp = characters[left];
            characters[left] = characters[right];
            characters[right] = temp;
            left++;
            right--;
        }

        return new String(characters);
    }

    public static void main(String[] args) {
        System.out.println(reverseString("Meta")); // Output: ateM
    }
}
This code effectively reverses the string by swapping characters from the ends towards the center, ensuring O(n) time complexity.
Software EngineerCore Concept
02
A Software Engineer was asked
SarthiQ Meta
Medium
Asked in 2025
Q. Write a function in Python to find the longest substring without repeating characters in a given string.
Ans. To find the longest substring without repeating characters, you can use a sliding window approach with two pointers. Here's how you can implement this in Python:
python
**def longest_unique_substring(s):**
    char_map = {}
    left = 0
    max_length = 0
    start = 0

**    for right, char in enumerate(s):**
**        if char in char_map and char_map[char] >= left:**
            left = char_map[char] + 1
        char_map[char] = right
**        if right - left + 1 > max_length:**
            max_length = right - left + 1
            start = left

    return s[start:start + max_length]

**Example usage**
print(longest_unique_substring('abcabcbb'))  # Output: 'abc'
print(longest_unique_substring('bbbbb'))    # Output: 'b'
print(longest_unique_substring('pwwkew'))   # Output: 'wke'
This function iterates over the string with the right pointer, while the left pointer marks the start of the current substring without duplicates. The dictionary char_map keeps track of the last occurrence of each character. When a duplicate character is found within the current window, the left pointer moves to the right of the last occurrence of that character to ensure all characters in the window are unique. The longest substring is updated accordingly.
Software EngineerCore Concept
03
Software Engineer
SarthiQ Meta
Hard

Question:

How would you design a scalable system for XYZ...

04
Backend Developer
SarthiQ Meta
Hard

Question:

How would you design a scalable system for XYZ...